Question

Amol attaches two appliances of resistance 4 ohms each in parallel and two that arrangement he attaches another appliance of resistance 8 ohms. If he is using a battery of 12 V .What is the total Current flowing in the circuit . Also draw the circuit diagram .​

Answer 1

Answer:

(a) For Parallel connection,

R

p

1

=

R

1

1

+

R

2

1

+

R

3

1

R

p

1

=

2

1

+

4

1

+

5

1

R

p

1

=

20

10+5+4

R

p

=

19

20

Ω

(b) R

1

=2Ω,R

2

=4Ω,R

3

=5Ω

I

1

=

R

1

V

=20/2=10A

I

2

=

R

2

V

=20/4=5A

I

3

=

R

3

V

=20/5=4A

Total current = I

1

+I

2

+I

3

=19A

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