Physics, asked by bhagyashribirari20, 4 months ago

Amol is an inspection incharge rejects 0.08% of the
items as defective. How many will he examine to
reject 4?
A. 3200
B. 5000
C. 4000
D. 4500​

Answers

Answered by amitnrw
1

Given : Amol is an inspection incharge rejects 0.08% of the items as defective.

To Find : How many will he examine to reject 4  

A. 3200

B. 5000

C. 4000

D. 4500​

Solution:

let say Item inspected  =  N

Rejected = 0.08 %

= (0.08/100)N

= 8N/10000

Rejected  = 4

=> 8N/10000 = 4

=> 8N = 40000

=> N = 5000

5000 items will be examined

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Answered by akshitanegi26
1

 \huge \cal ❖ \: \colorbox{pink}{ ANSWER} \: ❖

Let the items inspected be x.

Rejected = 0.08

= (0.08/100)x

=(8x/10000)

Rejected = 4

=> 8x/10000 = 4

=> 8x = 40000

x = 5000.

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