Question

amomg the 3 no ,the first is three times the second and third is five times the first.if the average of the 3 no is 57 the difference between the largest and smallest no

Answer 1

Answer :-

Let the three numbers be = x, y and z

According to the given question :-

x = 3y ...(1)

z = 5x ...(2)

We can also find that :-

3y = $\tt{\frac{z}{5}}$

y = $\tt{\frac{z}{15}}$ ...(3)

Average = 57

=》 $\sf{\frac{x+y+z}{3} = 57}$

Replace the values by (1),(2) and (3)

=》 $\sf{\frac{3y+y+15y}{3} = 57}$

=》 $\sf{\frac{19y}{3} = 57}$

=》 $\sf{y = 9}$

$\sf{x = 3y = 27}$

$\sf{z = 5x = 135}$