Question

among 14 consecutive integers the sum of the last 7 integer is 161 the sum of the first seven integer is​

Answer 1

Answer:

Sum of the first 7 integers is 112

Step-by-step explanation:

Let the 14 consecutive integers be x,x+1,x+2,.........x+13

Given:

Sum of last 7 integers = 161

(x+7) + (x+8)+........+(x+13)=161

7x+(7+8+9+10+11+12+13)=161

7x + 70 =161

7x = 91

x= 13

Now,

Sum of the first 7 integers

= x+(x+1)+..........+(x+6)

= 7x+(1+2+3+4+5+6)

= 7x+21

=7(13)+21

=91+21

=112