Question

among 21 components 3 are defective. what is the probability that a component selected at random is not defective ​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

GIVEN

• Among 21 components 3 are defective

• A component selected at random

TO DETERMINE

The probability that a component selected at random is not defective

CALCULATION

Here total number of components = 21

So the total number of possible

outcomes = 21

Among 21 components 3 are defective

So the number of non defective components are

$= 21 - 3$

$= 18$

Let A be the event that the randomly selected component is not defective

So the total number of possible outcomes for the event A is = 18

Hence the required probability

$= \sf{ P(A)\: }$

$= \displaystyle \sf{ \frac{18}{21} \: }$

$= \displaystyle \sf{ \frac{6}{7} \: }$

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Answer 2

As per the data given in the above question.

We have to find the probability of not defective components.

Step-by-step explanation:

Given ,

Total number of components= 21 components

Number of components are defective= 3 components

Number of components which are not defective= 21-3= 18 components.

Solution:

Solution:STEP-1:

Let P(E) be the probability of finding the not defective components.

Let sample n(s) be for the total components

Let event n(E) for non-defective components

STEP-2:

We know that ,

$Probability= \frac{events \: occured}{total \: events}$

$P(E) = \frac{n(E)}{n(s)}$

Put the values ,

$P(E) = \frac{18}{21}$

We can simplify the values by dividing 3,

$P(E) = \frac{18 \div 3}{21 \div 3}$

$P(E) = \frac{6}{7}$

Hence ,

Probability of random non-defective components is 6/7.

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