Among 5 green balls and 3 blue balls, how many selections can be made that atleast 3 green balls are selected
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Answered by
1
Answer:
8c5-(5c2+3c3)=56-11=45. then subtracting cases that has less than 3 green ball cases ,,,that leaves with only one case i.e 5c2+3c3 =>here we don't take 5c1 because we have only 3 blue balls.
Answered by
0
Answer:
9 selections
Step-by-step explanation:
3G - 1 B
3G - 2B
3G - 3B
4G - 1B
4G - 2B
4G - 3B
5G - 1B
5G - 2B
5G - 3B
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