Question

among 900 people in a state 90 are found to be chapati eaters construct 99% confidence interval for the true population​

Answer 1

Step-by-step explanation:

Given among 900 people in a state 90 are found to be chapati eaters construct 99% confidence interval for the true proportion.

• Given m = 90, n = 900
• Therefore P = m/n
•                    = 90 / 900
•                    = 1/10
•                    = 0.1
• Also Q = 1 – P
•             = 1 – 0.1
•            = 0.9
• Now we have √pq / n
•                    = √0.1 x 0.9 / 900
•                   = √0.0001
•                     = 0.01
• Now we have confidence interval = p +-Z α/2 (√pq/n)
•                                     So we have (0.1 + 0.03, 0.1 – 0.03)
•                                                       (0.07, 0.13)

Reference link will be

https://brainly.in/question/2770523

Answer 2

Answer:

(0.07,0.13)hope it helps you