Question

Among four children A, B, C and D, find the probability that no two of them were born on the same day of a week.
O a. 25/49
O b. 120/343
c. 20/49
O d. 24/49

Answer 1

answer:

120/343

Step-by-step explanation:

.Correct option is

C

120/343

Four people are chosen,

If no people have same birthdays then everyone has a different birthday.

So, the probability that no two people have same birthday is =

7

7

×

7

6

×

7

5

×

7

4

=

343

120

.

∴ Option C is correct.

Hence, the answer is

343

120