Among NaCl, BeCl2 and AlCl3, which one is more covalent? Justify the answer.
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The anion in all the options are same so we can rule them out .....therefore we are basically left with Na+ , Be2+ and Al3+ cations. Now according to Fajan's rule the compound having the smallest cation and the largest anion will be most covalent. As we know that more the number of electrons lost , greater will be the electrostatic force of attraction between the valence shells and the nucleus therefore decreasing its size. Hence, the answer here will be :
AlCl3> BeCl2> NaCl.....hope it helps
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