Among the following electrons which one has highest energy?
a)n=3 , l=2 , m=0 , s=+1/2
b)n=4 , l=0 , m=0 , s=+1/2
c)n=3 , l=1 , m=1 , s=-1/2
d)n=3 , l=0 , m=0 , s=-1/2
Correct option is a
Answers
Answered by
6
energy of an orbital is given by the sum of n and l
ie energy=n+l
higher the sum of n and l more is the energy
therefore we see that n+l for option a is 5 which is the highest among all
therefore the answer is option a
Answered by
1
Explanation:
option D is the correct answer❣️❣️❣️❣️❣️
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