Chemistry, asked by himanshin9542, 10 months ago

Among the following ethers, which one will produce methyl
alcohol on treatment with hot concentrated HI?
[2013]
(a) CH₃ - CH₂ - CH- O - CH₃
|
CH₃

CH₃
|
(b) CH₃ - C - O - CH₃
|
CH₃
(c) CH₃ - CH - CH₂ - O - CH₃
|
CH₃
(d) CH₃ – CH₂ – CH₂ – CH₂ – O – CH₃

Answers

Answered by King99041
0

Answer:

It's better to contact Google for perfect answer

Answered by brokendreams
0

Option B is the right answer.

Explanation:

  • The reaction of an ether with hydrogen iodide reacts via the protonation and carbocation formation.
  • Here the Proton of hydrogen iodide attacks the oxygen lone pair and forms an intermediate.
  • This intermediate is released by formation of carbocation.
  • Now the stability of carbocation varies as 3°>2°>1°.
  • So the 3° carbocation is formed in the case of option B.
  • The reaction process is attached below.
  • This gives methyl alcohol and isobutyliodide.

For more information about HI reactions,

https://brainly.in/question/6455505

What is the action of hot HI on ethyl methyl ether. give classification of phenols with examples

https://brainly.in/question/7468413

What is the action of cold hi on ethyl methyl ether? - Brainly.in

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