Question

Among the following series of transition metal
ions, the one where all metal ions have 3d2
electronic configuration is (At. nos. Ti = 22; V = 23; Cr = 24; Mn = 25)
(a) Ti³⁺ ,V²⁺ ,Cr³⁺ ,Mn⁴⁺
(b) Ti⁺,V⁴⁺ ,Cr⁶⁺,Mn⁷⁺
(c) Ti⁴⁺ ,V³⁺ ,Cr²⁺ ,Mn³⁺
(d) Ti²⁺ ,V³⁺ ,Cr⁴⁺ ,Mn⁵⁺

Answer 1

(d)  Ti2+, V3+, Cr4+, Mn5+  

Explanation:

The electronic configuration of the given elements are as follows:

Ti(22) - 3d2 4s2

V(23) - 3d2 4s2

Cr(24) - 3d4 4s2

Mn(25) - 3d5 4s2

For the respective ions, the electronic configuration will change to:

Ti2+ - 3d2

V3+ - 3d2

Cr4+ - 3d2

Mn5+ - 3d2

We find that Ti2+, V3+, Cr4+, Mn5+ have 3d2 electronic configuration.

Option D is the answer.