Question

Among the following solutions
1. 0.01 M NaCl
IL. 0.05M Gulcose
III. 0.01M CaCl2
IV.0.02M KCI
the correct order of decreasing boiling point can be given as​

Answer 1

Glucose,kcl,cacl2,Nacl

Explanation:

hope this is helpfull

Answer 2

Answer:

IV > III = II > I

Explanation:

Boiling points of liquids can be determined using the capillary method. In this method, a reverse capillary tube is placed in the liquid to be tested and the liquid is heated. As the temperature rises, the air in the capillary escapes and is replaced by liquid vapor.

Given: Boiling point of Nacl, Glucose, $CaCl_2$, $KCl$

Checking the options one by one to arrange them in decreasing order

(i) 0.1 M glucose: final concentration is 0.1 M because it does not dissociate in the solution

(ii) 0.2 M urea: This also does not dissociate. Final concentration = 0.2 M

(III) 0.1 M NaCl: dissociates into Na + and Cl - to generate two ions. Final concentration = $0.1$× $2 = 0.2 M$

(IV) 0.5M $CaCl_2$, Dissociate to produce 3 ions.

Final concentration$= 0.5$ × $3 = 1.5 M$

What will be the molecular weight of a chemical, consisting 2 moles of H2SO4, 3 moles of SO2 and 1 mole of NaOH? (Na=23, O=16, H=1 S=32)

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Dry corrosion is also called as

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