Question

Among the following, the correct order of acidity is [2016]
(a) HClO₃ < HClO₄ < HClO₂ < HClO
(b) HClO < HClO₂ < HClO₃ < HClO₄
(c) HClO₂ < HClO < HClO₃ < HClO₄
(d) HClO₄ < HClO₂ < HClO < HClO₃

Answer 1

Answer:

Among the following, the correct order of acidity is [2016]

(a) HClO₃ < HClO₄ < HClO₂ < HClO

(b) HClO < HClO₂ < HClO₃ < HClO₄

(c) HClO₂ < HClO < HClO₃ < HClO₄

(d) HClO₄ < HClO₂ < HClO < HClO₃

Hope this helps you ❤️

Answer 2

HClO < HClO₂ < HClO₃ < HClO₄ is the correct order.

Explanation:

• Chlorine forms 4 oxyacids and one normal acid which is the hydrochloric acid.

• The four oxyacids are hypochlorous acid i.e HClO, chlorous acid i.e HClO2, Chloric acid i.e HClO3 and perchloric acid i.e HClO4.

• The hypochlorous acid contains one oxygen-chlorine bond where the hydrogen is attached with tye namaste oxygen.

• In case of HClO2, out of the three lone pairs of electrons that are present in chlorine, one is donated to oxygen.

• Similarly in HClO3 and HClO4, two and all the three lone pairs are donated to oxygen.

• Now oxygen being more electronegative than chlorine, draws the electron pairs more towards themselves.

• So more the number of oxygen, more the chlorine becomes electron deficient.

• So chlorine will draw more electron from the single bonded oxygen which then draws the electron from Proton and let's it freely dissociate.

• So more the number of oxygen attached to chlorine, more is the acidity.

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