Question

Among the following, the solution which exhibits least colligative property is
a) 500ml of 0.1M sucrose solution
b) 250 ml of 0.5M glucose solution
c) 1000ml of 0.02M urea solution
d) 1 litre of 0.5M NaCl solution​

Answer 1

Answer:

1000ml of 0.02M urea solution

Answer 2

Among the following, the solution which exhibits least colligative property is  

250 ml of 0.5M glucose solution.

Explanation:

Colligative properties

They are the properties that depend upon number of moles of solute .

Let us find out the number of moles in these cases :

1. 500 ml of 0.1M sucrose solution

Molarity = no. of moles /volume in Litres

0.1 =No. of mole /0 .5

No. of mole = 0.1 x 0.5 = .05 moles

2. 250 ml of 0.5M glucose

Molarity = mole /volume

0.5=mole / 0.25

mole = 0.5 x 0.25 =0.125mol

3.1000ml of 0.02M urea

mole = 1 x 0.02 = .02 mol

4.1 Litre of 0.5M NaCl

mole = Molarity x volume

mole =0.5 x 1 = .05 mole

The 250 ml of 0.5M glucose solution will have least value of colligative property that is = .125mol .