Among the values x=3 and x=-1/√2, which one is the solution of equation √2x²+(1-3√2)x-3=0
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Step-by-step explanation:
if X=3
√2(3)^2+(1-3√2)3-3
=9√2+3-9√2-3
=o
=r.h.s
if X=-1/√2
√2(-1/√2)^2+(1-3√2)(-1/√2)-3
=√2/2-1/√2+3-3
=1/√2-1/√2+3-3
=0
=r.h.s
both are right
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