Question

Among the values x=3 and x=-1/√2, which one is the solution of equation √2x²+(1-3√2)x-3=0​

Answer 1

Step-by-step explanation:

if X=3

√2(3)^2+(1-3√2)3-3

=9√2+3-9√2-3

=o

=r.h.s

if X=-1/√2

√2(-1/√2)^2+(1-3√2)(-1/√2)-3

=√2/2-1/√2+3-3

=1/√2-1/√2+3-3

=0

=r.h.s

both are right