Question

Among three consecutive positive even number, the sum of 2/5 of the first and half of the second is 11 less than the third number. Find those three number

Answer 1

Answer:

Let 1st number is x.

So, another numbers = ( x + 2 ) and ( x + 4 ).

Given,

⇒ 2/5th of 1st no. + 1/2 of 2nd no. = 3rd no. - 11

⇒ { ( x )2/5 } + { ( x + 2 ) 1/2 } = x + 4 - 11

⇒ ( 2x / 5 ) + { ( x/2 ) + 1 } = x - 7

4x + 5x + 10

⇒ ___________________ = ( x - 7)

10

⇒ ( 9x + 10 ) ÷ 10 = ( x - 7 )

⇒ ( 9x + 10 ) = 10 ( x - 7 )

⇒ 9x + 10 = 10x - 70

⇒ 10x - 9x = 70 + 10

∴ x = 80.

1st no. = x = 80

2nd no. = ( x + 2 ) = ( 80 + 2 ) = 82

3rd no. = ( x + 4 ) = ( 80 + 4 ) = 84.

Numbers are 80,82 and 84.

Step-by-step explanation:

Hope it helps you!

Answer 2

Let the three consecutive positive even numbers be x,x+2 and x+4.

ATQ. 2/5 × x + 1/2 × x+2 =x+4 - 11

=> 2x/5 + x/2 + 2 = x -7

=> 4x + 5x + 10/ 10 = x-7

=> 9x + 10/ 10 = x-7/ 1

=> 1(9x + 10) = 10(x - 7)

=> 9x + 10 = 10x - 70

=> 10 + 70 = 10x - 9x

=> 10x - 9x = 10 + 70

=> x = 80

Value of the three consecutive positive even numbers :-

x = 80

x + 2 = 80 + 2 = 82

x + 4 = 80 + 4 = 84

:. Thus, The three consecutive positive even numbers are 80,82 and 84.