Among three consecutive positive even numbers, the sum o
than the third number. Find those three numbers.
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Let 1st number is x.
So, another numbers = ( x + 2 ) and ( x + 4 ).
Given,
⇒ 2/5th of 1st no. + 1/2 of 2nd no. = 3rd no. - 11
⇒ { ( x )2/5 } + { ( x + 2 ) 1/2 } = x + 4 - 11
⇒ ( 2x / 5 ) + { ( x/2 ) + 1 } = x - 7
4x + 5x + 10
⇒ ___________________ = ( x - 7)
10
⇒ ( 9x + 10 ) ÷ 10 = ( x - 7 )
⇒ ( 9x + 10 ) = 10 ( x - 7 )
⇒ 9x + 10 = 10x - 70
⇒ 10x - 9x = 70 + 10
∴ x = 80.
1st no. = x = 80
2nd no. = ( x + 2 ) = ( 80 + 2 ) = 82
3rd no. = ( x + 4 ) = ( 80 + 4 ) = 84.
banderajesh99:
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