Question

among three consecutive positive even numbers the sum of 2/5 of the first and half of the second is 11 less than the third number find those there numbers

Answer 1

Let 1st number is x.

So, another numbers = ( x + 2 ) and ( x + 4 ).

Given,

⇒ 2/5th of 1st no. + 1/2 of 2nd no. = 3rd no. - 11

⇒ { ( x )2/5 } + { ( x + 2 ) 1/2 } = x + 4 - 11

⇒ ( 2x / 5 ) + { ( x/2 ) + 1 } = x - 7

           4x + 5x + 10
⇒  ___________________  = ( x - 7)
                    10

⇒  ( 9x + 10 ) ÷ 10 = ( x - 7 )

⇒ ( 9x + 10 ) = 10 ( x - 7 )

⇒ 9x + 10 = 10x - 70

⇒ 10x - 9x = 70 + 10

∴ x = 80.

1st no. = x = 80

2nd no. = ( x + 2 ) = ( 80 + 2 ) = 82

3rd no. = ( x + 4 ) = ( 80 + 4 ) = 84.


Numbers are 80,82 and 84.