Question

Among three numbers the first is thrice the second number and one-fourth of the third number. the average of all three numbers is 64.what is the

Answer 1

Let the three numbers be x, y and z.

Acc. to question, 

x = 3y = z/4.

Now, let x = 3y = z/4 = k.

So, we'll get x = k; y = k/3; z = 4k.

Now, average of these three numbers will be:

(k + k/3 + 4k)/3

or, (  (3k+k+12k) / 3  )   /  3

or,  16k/9.

Now, in the question, it was given that average is 64.

So, comparing we get, 16k/9 = 64.

or, 16k = 64 x 9

or, k = 576/16 = 36. 

Therefore, the required numbers are:
after substituting the value of k we get,
x=36,  y=36/3=12  and   z=4x36=144.  (Ans)