Math, asked by mirahmedali6385, 10 months ago

Among three numbers, the first is twice the second and thrice the third, if the average of three numbers is 517, then what is the difference between the first and the third number?

Answers

Answered by tanujrbgs
10

Answer:

564

Step-by-step explanation:

6y+3y+2y = 517*3=1551

11y = 1551

y= 1551/11

141

First no. - third no. =6y-2y=4y=4*141=564

Answered by cbiinfra350
0

Answer:

564

Step-by-step explanation:

X=2y and x=3z

As per question, (x +y+z) /3 = 517

X+y+z =517 *3 = 1551

2y +y + 2y/3 = 1551

11y/3 = 1551

Y = 423

Hence, x=>2*423 = 846 & z=> 846/3 = 282

Difference of first - third = 846 - 282 = 564

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