Question

Among three numbers, the first is twice the second and thrice the third. If the average of three numbers is 396, then what is the difference between the first and the third number?

A) 594 B) 448 C) 432 D) 453

Answer 1

Answer :-

Option c) 432

Assumption :-

x - first number

y - second number

z - third number

Given :-

x = 2y ; x = 3z

1/3(x+y+z) = 396 (1)

Expln:-

x = 2y ; x = 3z

By (1) 1/3(x+y+z) = 396

x+ x/2 + x/3 = 1188

(6x+3x+2x)/6 = 1188

11x = 7128

x = 648

x = 2y x = 3z

y = 648/2 z = 648/3

y = 324 z = 216

The difference between the first and the third number :-

x-z = 648 - 216 = 432 ✿•°•°•°•°