among two discs A and B , first have radius 10 cm and charge 10^-6 Micro Coulomb and second have a radius of 30 cm and charge 10^-5 Coulomb . when they are touched, charge on both Qa and Qb respectively will be?
Answers
Answer ⇒ Final charge on both body is, q₁ = 2.75 × 10⁻¹² C. and q₂ = 8.25 × 10⁻¹² C.
Explanation ⇒
After the two disc are kept in constant there potential becomes same.
∴ Potential of A = kq₁/r₁
r is the radius of sphere and q is its charge.
Potential at B = kq₂/r₂
When potential becomes same.
then, q₁/r₁ = q₂/r₂
∴ q₁/10 = q₂/30
q₂ = 3q₁
Now, we know that charge remains the conserved.
Thus, Sum of both the charges is cosnatnt before and after connecting both bodies.
q₁ + q₂ = 10⁻¹² C + 10⁻¹¹ C
∴ 4q₁ = 1.1 × 10⁻¹¹
∴ q₁ = 2.75 × 10⁻¹² C.
q₂ = 8.25 × 10⁻¹² C.
Hope it help.s
Answer ⇒ Final charge on both body is, q₁ = 2.75 × 10⁻¹² C. and q₂ = 8.25 × 10⁻¹² C.
Explanation ⇒
After the two disc are kept in constant there potential becomes same.
∴ Potential of A = kq₁/r₁
r is the radius of sphere and q is its charge.
Potential at B = kq₂/r₂
When potential becomes same.
then, q₁/r₁ = q₂/r₂
∴ q₁/10 = q₂/30
q₂ = 3q₁
Now, we know that charge remains the conserved.
Thus, Sum of both the charges is cosnatnt before and after connecting both bodies.
q₁ + q₂ = 10⁻¹² C + 10⁻¹¹ C
∴ 4q₁ = 1.1 × 10⁻¹¹
∴ q₁ = 2.75 × 10⁻¹² C.
q₂ = 8.25 × 10⁻¹² C.❤️