Question

among two supplement angles, the measure of the large angle is 36° more than the measure of the smaller. find the measures

Answer 1

let the smaller angle=x

so larger be=x+36

ATQ..

x+x+36=180

2x=144

x=72

Smaller angle=x=72 degree

larger angle=x+36=72+36=108 degree

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hope it helps you

Answer 2

Let the major of the smaller angle bex

then larger angle=X+36

We know that the sum of the supplementary angle is 180 degrees.

Now according to question

X+X+36=180

2x=180-36

2x=144

X=72

Therefore larger angle equal to 72+36=108

hope it will help you