Question

Among two supplementary angles, the measure of the larger angle is 36° more than the measure of the smaller. find their measures.​

Answer 1

Step-by-step explanation:

x+y =180°

(x)+(x+36°) = 180°

2x + 36°=180

2x =180°-36°= 144°

x = 144 /2 = 72°

So measures of two angles are 108°(72+36) and 72°

Mark me as brainliest if you understood this answer.

Answer 2

Let us assume supplementary be x° and (180 - x)°

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From the question,

The measure of the larger angle is 36° more than the measure of the smaller angle, let the larger angle be x°.

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Then,

$\implies(180 - x) + 36 = 6 \\ \implies216 - x = x \\ \implies216 = x + x \\ \implies216 = 2x \\ \implies x = 216/2 \\ \sf Largest \: angle = 180 \degree \\ \sf Smallest \: angle = (180 - 36)° \\ \sf \blue{72} \: { \mathfrak{ \underline \red{Answer!}}}$

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Hope it help you.