among two supplementary angles, the measure of the larger angle is 36° more than the measure of the smaller. Find their measures.
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Let us assume supplementary be x
∘
and (180−x)
∘
From the question,
The measure of the larger angle is 36
∘
more than the measure of the smaller angle, let the larger angle be x
∘
.
Then,
⟹(180−x)+36=x
⟹216−x=x
⟹216=x+x
⟹216=2x
⟹x=216/2
⟹x=108
Larger angle =108∘
Smaller angle =(108−36)∘
=72
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