among two supplementary angles the measure of the larger angle is 36 degree more than the measure of the similar find their measures
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sum of two supplementary angle = 180°
let small angle be x then larger angle is x +36
x + x +36= 180
2x = 180- 36
2x = 144
x = 72•
then larger is 108°
let small angle be x then larger angle is x +36
x + x +36= 180
2x = 180- 36
2x = 144
x = 72•
then larger is 108°
Answered by
9
Let the measures of smaller angle be x and larger angle be x + 36°
A/q,
x + x + 36° = 180°
=> 2x = 180° - 36°
=> 2x = 144°
=> x = 144°/2
=> x = 72°
•°• Required angles measures
smaller angle = x = 72°
and larger angle = x + 36° = 72 + 36 = 108°
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