Among two supplementary angles the measure of the measure of the largest angle is 44 degree more than the measure of the smaller find the their measure
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let one angle be x
second angle = 44 + x
A.T.Q
x + 44 + x = 180(supplementary angles)
2x= 180-44
x = 136/2
x= 68
first angle = x = 68
second angle = 68+44
=112
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second angle = 44 + x
A.T.Q
x + 44 + x = 180(supplementary angles)
2x= 180-44
x = 136/2
x= 68
first angle = x = 68
second angle = 68+44
=112
HOPE THIS WOULD HELP YOU
mark me as brainliest
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