Among two supplementry angles the measure of the larger angle is 20 times more than the smaller angle . Find their measures.
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The measure of the angles are (60/7)°,(1200/7)°
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Solution :
Let the smaller angle be x°.
Therefore, its supplement larger angle = (x + 20)°
Since, the sum of two supplement angles is 180°.
x + (x + 20)° = 180°
x° + x° + 20° = 180°
2x °+ 20° = 180°
On transposing 20° from LHS to RHS, we get
2x = 180° - 20°
2x° = 160°
On dividing both sides by 2, we get
= 2x°/2 = 160/2
x = 80
Hence, the smaller angle is 80°
and its supplement larger angle = 80° + 20° = 100°
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