among two supplementry angles the mesure of the larger angle is 44 degree more than the mesure of the smaller .find their measure
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let 1st angle=x
2nd angle= x+44
both are supplementary so their sum will be 180
x+x+44=180
2x= 180-44
and x= 68
so angles will be 68 and 68+44=112
2nd angle= x+44
both are supplementary so their sum will be 180
x+x+44=180
2x= 180-44
and x= 68
so angles will be 68 and 68+44=112
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