amonia mole one n2 and h3 now amonia symbol and naitrogen jojota?
Answers
Answered by
1
ANSWER
Given reaction for the formation of ammonia-
N
2
+3H
2
⟶2NH
3
From the above reacton,
1 mole of N
2
reacts with 3 moles of H
2
.
Therefore,
6 moles of N
2
will react with 18 moles of H
2
.
Given amount of H
2
=6 moles
Therefore, H
2
is the limiting reagent.
Therefore,
Again from the above reaction.
No. of moles of ammonia formed when 3 moles of H
2
react with excess of N
2
=2
∴ No. of moles of ammonia formed when 6 moles of H
2
react with excess of N
2
=
3
2
×6=4 moles
Hence 4 moles of ammonia are formed when 6 moles of N
2
react with 6 moles of H
2
.
Answer ByavatarToppr
SHARE
ASK
Get Instant Solutions, 24x7
No Signup required
girl
More Questions by difficulty
EASY
MEDIUM
HARD
Similar questions
English,
4 months ago
Math,
4 months ago
Math,
8 months ago
CBSE BOARD X,
11 months ago
History,
11 months ago