Question

amonia mole one n2 and h3 now amonia symbol and naitrogen jojota?​

Answer 1

ANSWER

Given reaction for the formation of ammonia-

N

2

+3H

2

⟶2NH

3

From the above reacton,

1 mole of N

2

reacts with 3 moles of H

2

.

Therefore,

6 moles of N

2

will react with 18 moles of H

2

.

Given amount of H

2

=6 moles

Therefore, H

2

is the limiting reagent.

Therefore,

Again from the above reaction.

No. of moles of ammonia formed when 3 moles of H

2

react with excess of N

2

=2

∴ No. of moles of ammonia formed when 6 moles of H

2

react with excess of N

2

=

3

2

×6=4 moles

Hence 4 moles of ammonia are formed when 6 moles of N

2

react with 6 moles of H

2

.

Answer ByavatarToppr

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