Question

amount of charge required to convert 17gm of H2O2 into O2

Answer 1

2H2O2 → 2H2O + O2

here We use redox reaction ,

H2O2 → O2 + 2H+ +2e ------(1)
2H+ +H2O2→ H2O + H2O -2e

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here we see from eqn (1) 1 mole H2O2 convert 2mole of electrons released,

mole of H2O2 = 17/34 = 1/2 =0.5 mole
for 0.5 mole amount of charge required
= 0.5 × 2 × 6.023 × 10²³ × 1.6 × 10^-19
= 6.023 × 1.6 × 10⁴ C
≈ 9.6 × 10⁴ C

Answer 2

W=E.wt×Q/96500 from faraday law

E=34/2=17

W=17Q/96500

17=17Q/96500

::Q=96500=1F