Question

amount of copper deposited when 2f is passed through cuso4 solution (atomic mass of cu is 63.5g)​

Answer 1

Explanation:

Refer above attachment

Answer 2

Given:

2F is passed through CuSO4 solution.

To find:

Amount of Copper deposited?

Calculation:

First, let's write the half cell reaction:

$Cu^{+}+2e^{-}\rightarrow Cu$

Now, from the reaction, we know that :

• 2 moles of electrons [or 2 Faraday (F)] of electricity is needed to deposit 1 mole of Copper.

Now, applied charge is 2F.

So, amount of Copper deposited is 1 mole or 63.5 grams.

Hope It Helps.