Amount of dilute sulphuric acid are in the ratio 2:1 and another acid in ratio 1:3
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Explanation:
Let the percentage of water be X
The quantity of new mixture = (5X/3) + (3X/2 )+ (4X/3) = 27X/6 = 9X/2.
Percentage of milk = (5X/3) x (3/5) + (3X/2) x (2/3) + (4X/3) x (3/4) = 3X
Percentage of water = (5X/3) x (2/5) + (3X/2) x (1/3) + (X/2) x (2/3) = 3X/2
Percentage of water = (3X/2)/(9X/2) x 100 = 100/3 = 33 (1/3)%
Let the percentage of water be X
The quantity of new mixture = (5X/3) + (3X/2 )+ (4X/3) = 27X/6 = 9X/2.
Percentage of milk = (5X/3) x (3/5) + (3X/2) x (2/3) + (4X/3) x (3/4) = 3X
Percentage of water = (5X/3) x (2/5) + (3X/2) x (1/3) + (X/2) x (2/3) = 3X/2
Percentage of water = (3X/2)/(9X/2) x 100 = 100/3 = 33 (1/3)%
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