Amount of energy that can be stored from Faraday flashlight / linear alternator?
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I will phrase it in civil engineering terms.
a capacitor is a reservoir, the voltage across the capacitor is equal to the depth of water behind the dam; the reservoir integrates water flow over time, the capacitor integrates charge flow over time.
the capacitance of the capacitor can be though of as the amount of charge flow required to raise its voltage by a volt; the capacitance of the reservoir is the water flow into it required to raise its level by one foot. a "large" capacitor is one in which the amount of charge flow into it needed to raise its voltage by one volt is large; a "large" reservoir is one in which the amount of water flow into it required to raise its level by one foot is large. the surface area of the reservoir is hence related by analogy to the capacitance rating of the capacitor.
the energy stored in the capacitor e = (1/2) cv^2 where c is the capacitance of the capacitor and v is the voltage. You know how to calculate the energy stored in the reservoir, yes?
Model the shaken coil generator as a pump with a piston and some check valves to prevent backflow. Now you can see that one stroke of the pump is analogous to one current surge from the generator and the voltage rise of the capacitor with pump strokes scales exactly as the amount of water level rise in the reservoir as the pump fills it.
This analogy should allow you to do the algebra required to solve your problem. let us know it if isn't. best regards, niels
a capacitor is a reservoir, the voltage across the capacitor is equal to the depth of water behind the dam; the reservoir integrates water flow over time, the capacitor integrates charge flow over time.
the capacitance of the capacitor can be though of as the amount of charge flow required to raise its voltage by a volt; the capacitance of the reservoir is the water flow into it required to raise its level by one foot. a "large" capacitor is one in which the amount of charge flow into it needed to raise its voltage by one volt is large; a "large" reservoir is one in which the amount of water flow into it required to raise its level by one foot is large. the surface area of the reservoir is hence related by analogy to the capacitance rating of the capacitor.
the energy stored in the capacitor e = (1/2) cv^2 where c is the capacitance of the capacitor and v is the voltage. You know how to calculate the energy stored in the reservoir, yes?
Model the shaken coil generator as a pump with a piston and some check valves to prevent backflow. Now you can see that one stroke of the pump is analogous to one current surge from the generator and the voltage rise of the capacitor with pump strokes scales exactly as the amount of water level rise in the reservoir as the pump fills it.
This analogy should allow you to do the algebra required to solve your problem. let us know it if isn't. best regards, niels
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The answer of u r question is..✌️✌️
Is in the pic.
Thank you..⭐️⭐️⭐️
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