Question

Amount of h2o2 present in 1l of 1.5n h2o2 solution is

Answer 1

The answer is 25.5g. It can be done as follows:

Answer 2

Given:

Normality of the $H_2O_2$ solution = 1.5 N

To find:

Amount of h2o2 present in the solution = ?

Formula to be used:

1. Equivalent weight = $\frac{Molar mass}{n-factor}$
2. Normality = $\frac{mass of solute}{Equivalent weight of solute\times volume of solution}$

Calculation:

Equivalent weight of $H_2O_2$ =  $\frac{Molar mass}{n-factor}$ = $\frac{34}{2}=17$

Substituting the obtained value in normality formula, it gives:

Normality = $\frac{mass of solute}{Equivalent weight of solute\times volume of solution}$

1.5 = $\frac{m}{17\times1} = \frac{m}{17}$

1.5× 17 = m

25.5 = m

Conclusion:

25.5g of $H_2O_2$ is present in 1 L of 1.5 N $H_2O_2$ Solution.

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