Question

amount of heat released when 0.1 mole of HNO3 neutralized by 0.1 mole of koh in water is
(1_57•1kj. 2_13•7kj. 3_5•71kj.
4_1•37kj)​

Answer 1

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Answer 2

The amount of heat released when 0.1 moles of HNO3 are neutralized by 0.1 moles of Koh in water is 5.71Kj.

• The heat of neutralisation or enthalpy of naturalisation is equal to the amount of heat released when 1 mole of strong acid reacted with 1 mole of strong base to produce salt and water.
• The heat of neutralisation is exothermic as the new interaction is more stable.
• It is equal to 57.1 Kj for 1 mole or 13.6 Kcal.
• HNO3 and KOH are strong acids and strong bases respectively. so, the heat of neutralisation for 1 mole will be equal to 57.1 Kj/mol.
• The heat of neutralisation for 0.1 moles = 57.1×0.1 = 5.71Kj/mol.