Question

amount of ideal gas double krne par efficiency constant rhega?​

Answer 1

Answer:

work done by the gas is positive

Explanation:

For isothermal process,

dU=0

Work done =dW=p(V  

2

​  

−V  

1

​  

)

∴dW=+pV            [∵V  

2

​  

=2V  

1

​  

=2V]