Question

Amount of

NaOH

present in

200 ml

of

0.5N

solution is​

Answer 1

Answer:

1N NaOH = 40 g NaOH in 1000 mL of the solution = 1 mole of NaOH in 1000 mL of the solution. 0.5 N NaOH = 20 g NaOH in 1000 mL of the solution = 0.5 mole of NaOH in 1000 mL of the solution.

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