Question

amount of NaOHrequired to produce 250 cm cube of 1 molar solution in grams is:​

Answer 1

To calculate this use the following equation:

M*V=moles

where M is the molarity or mol/L and V is the volume in liters. Given the amounts in the question the molarity will be 1 M, the volume will be 250 mL or 0.25 L. So, the number of moles needed will be:

1 moles/L * 0.25 L = 0.25 moles

The molecular weight of NaOH is 23+17 = 40 g/mole so the amount needed is

0.25 moles * 40 g/mole of NaOH = 10 g of NaOH

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Answer 2

Answer:

10 g of NaOH

Explanation:

To calculate this use the following equation:

M*V=moles

where M is the molarity or mol/L and V is the volume in liters. Given the amounts in the question the molarity will be 1 M, the volume will be 250 mL or 0.25 L. So, the number of moles needed will be:

1 moles/L * 0.25 L = 0.25 moles

The molecular weight of NaOH is 23+17 = 40 g/mole so the amount needed is

0.25 moles * 40 g/mole of NaOH = 10 g of NaOH