Chemistry, asked by lousistron4220, 1 year ago

Amount of oxygen gas present in a 2 l vessel at 5 atm pressure and 27c is

Answers

Answered by Tejaswinisree
4
gn data

volume =2l
pressure =5atm
temperature =27°c
=27+273k
=300k



n=?

wkt
PV=nRt

n=PV/Rt
n=5*2/0.0821*300.

=10/24.63
=0.406moles


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