Amount of oxygen required for combustion
of 1 kg of a mixture of butane and
isobutane will be:
Answers
Answered by
9
Answer:
3.586 Kg
Explanation:
Butane and isobutane has the same molecular formula C
4
H
1
0
C
4
H
10
+
2
13
O
2
→4CO
2
+5H
2
O
58g of C
4
H
10
requires O
2
=
2
13
×32
1000g of C
4
H
10
requires O
2
=
2×58
13×32×1000
= 3.586 Kg
Answered by
0
Answer:
Butane and isobutane has the same molecular formula C4 H 1 0
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