Question

Amount of work done in moving a charge of 10 electrons from point of lower potential of 6V to the point of
higher potential of 11V is n X 10^-18 Joules. Find n.​

Answer 1

Answer:

5 volt

Explanation:

For 1 C charge, the number of electrons required are 6.25×10

18

Therefore, when 12.5×10

18

electrons are moving, corresponding charge is Q=2 C

work done =QΔV=10 J

Then,

ΔV=

Q

10

=

2

10

=5 V