Amount of work done in moving a charge of 10 electrons from point of lower potential of 6V to the point of
higher potential of 11V is n X 10^-18 Joules. Find n.
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Answer:
5 volt
Explanation:
For 1 C charge, the number of electrons required are 6.25×10
18
Therefore, when 12.5×10
18
electrons are moving, corresponding charge is Q=2 C
work done =QΔV=10 J
Then,
ΔV=
Q
10
=
2
10
=5 V
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