Amount of work doneto accelrate a 1000 kg of car ftom 20 to 30 ms in 1 s
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Answer:
Work done = Force × displacement
Force = ma = 1000×a = 1000a
Displacement = (v² - u²) / 2a
Displacement = (30² - 20²)/2a = (30-20)(30+20)/2a
= 10×50/2a
= 250 / a
Work done = 1000a × 250/a = 1000×250
= 250000 J
= 250 KJ
#WMK
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