Physics, asked by hassanjan, 10 months ago

Amount of work doneto accelrate a 1000 kg of car ftom 20 to 30 ms in 1 s

Answers

Answered by karanjotgaidu

1

Answer:

Work done = Force × displacement

Force = ma = 1000×a = 1000a

Displacement = (v² - u²) / 2a

Displacement = (30² - 20²)/2a = (30-20)(30+20)/2a

= 10×50/2a

= 250 / a

Work done = 1000a × 250/a = 1000×250

= 250000 J

= 250 KJ

#WMK

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