Question

amount of zinc required to produce 1.12 ml of hydrogen at STP on treatment with dilute HCl

Answer 1

heya....


The balanced equation is :

Zn + 2HCl ---> ZnCl₂ + H₂

1mole of Zn produces 1 mole of H₂

1mole of Hydrogen gasoccupies 22.4lit ( 0r 22400ml)at STP.

22400ml of Hydrogen gas is produced from 1mole of Zn(65g)

22400ml of H₂ ------> 65g of Zn

1.12ml of H₂ -----?

=( 65*1.12)/22400

= 3.25 x 10⁻³g

=32.5x 10⁻⁴g

∴AMOUNT OF Zn required is

32.5x 10⁻⁴g



tysm..#gozmit

Answer 2

Zn + 2HCl -----> H2 + ZnCl2

Now it is given in the question that 1.12 ml at STP is formed


look at the equation carefully

you will see 

1 mole of Zn gives you 1 mole of H2

so ...yea its on this basis we will be solving the rest of this question

1.12 ml of H2 is how many moles

1.12/22.4 = .05 moles

so 0.05 moles of Zn is required

0.05 * 65.4 = 3.27g (by the way 65.4g is the molar mass of Zn.,,,