Question

amount, which in 3 years gives < 1200 as the simple interest at the rate of 4% per annum?
What will be the compound interest at the rate of 10% per annum for 3 years on a principal
141​

Answer 1

Answer:

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Answer 2

Answer:

11,200 ; 46.671

Step-by-step explanation:

1st case:

Given,

S.I.= 1200

Rate of Interest = 4% p.a.

Time = 3 years

To find,

Amount = ?

Solution,

P= (S.I.× 100) ÷ (T × R)

P = (1200 × 100)÷(3 × 4)

P = 10,000

Amount = P + S.I.

Amount = 10,000+1200

Amount = 11,200

2nd case:

Given,

P = 141

T = 3 years (n = 3)

r = 10%

To find,

C.I. = ?

Solution,

C.I. = F.A. - O.P.

F.A. = P*(1+r÷100)^n

F.A. = 141*(1+10÷100)^3

F.A. = 141*(11÷10)^3

F.A. = (141*1331)÷1000

F.A. = 187.671

C.I. = 187.671 - 141.000

C.I. = 46.671

Therefore,

Amount for 1st case = 11,200;

C.I. for 2nd case = 46.671.