Question

& A, B and C can complete a work seperately
24, 36 and 48 days respectively. They started
together but C left after 4 days of start and A
left 3 days before the completion of work in
how many days will the work be completed?​

Answer 1

Answer:

Let the total work be W

speed of A =W/24

speed of B=W/36

speed of C=W/48

let the work takes x days

then ,W/48 ×4 +W/24 ×(X-3) +W/36 ×X=W

solving we get x =15 days