Question

& A two digit number is obtained by either by multiplying the of digits by 8 and subtracting multiplying the differenceof the digit by 16 and then sum of ses by adding 3.​

Answer 1

Let the tenth's digit be x and one's digit be y.

Then the number is 10x+y.

By the first condition-

(x+y)×8−5=10x+y

⇒2x−7y=−5 ---------(i)

By the second condition-

(x−y)×16+3=10x+y

⇒6x−17y=−3 -----------(ii)

Multiplying (i) by 3, we get

6x−21y=−15 --------(iii)

Subtracting (ii) from (iii), we get

−4y=−12

⇒y=3.

Substituting y=3 in (i)

2x−7×3=−5

⇒x=8

∴ The number is 10×8+3=83.