Question

& AF, BD and CE altitudes of A bc( are equal.
Prove that ABC is an equilateral triangle.​

Answer 1

Answer:

ALTITUDE OF SIDE SIDE

AF BC

BD AC

CE AB

AREA OF TRIANGLE = 1/2 × ALTITUDE × SIDE

= 1/2 × AF × BC

= 1/2 × BD × AC

= 1/2 × CE × AB

AF= BD= CE ( GIVEN IN QUESTION)

Step-by-step explanation:

SO,

1/2 AND ALTITUDES WILL BE CANCELLED

WE GET

BC= AC= AB

WE KNOW THAT SIDE OF EQUILATERAL TRIANGLE ARE ALWAYS SAME

SINCE

IT PROVE