Question

& an object of mass 22 kg is at certain
height above the ground. If the potential
energy of the object is 800J. Find the
height at
which the object is with
respect
ground by taking g=10ms"
​

Answer 1

Answer:

• 3.63 metres is the required answer.

Step-by-step explanation:

According to the Question

It is given that,

• Mass of object ,m = 22kg
• Potential Energy ,PE = 800 J
• Acceleration due to gravity ,g = 10m/s²

we have to calculate the height at which the object is with respect to ground .

As we know that Potential energy is the energy possess by body due to its height .

Let the height be h m

• PE = mgh

substituting the value we get

↠ 800 = 22 × 10 × h

↠ 800 = 220 × h

↠ h = 800/220

↠ h = 3.63 m

• Hence, the height at which the object is kept is 3.63 metre.

Answer 2

$\star \; {\underline{\boxed{\orange{\pmb{\frak{ \; Given \; :- }}}}}}$

• Potential Energy = 800 J
• Mass = 22 kg
• Force of Gravitation = 10 m/s

$\star \; {\underline{\boxed{\red{\pmb{\frak{ \; To \; Find \; :- }}}}}}$

• Height = ?

$\\ \qquad{\rule{200pt}{2pt}}$

$\star \; {\underline{\boxed{\color{darkblue}{\pmb{\frak{ \; SolutioN \; :- }}}}}}$

$\maltese$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ P.E = Mass \times Gravity \times Height }}}}}$

Where :

• P.E = Potential Energy

$\maltese$ Calculating the Height :

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { P.E = Mass \times Gravity \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 800 = 22 \times 10 \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 800 = 220 \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \dfrac{800}{220} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \cancel\dfrac{800}{220} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{\pmb{\sf{ Height = 3.63 \; m }}}}} \; {\pink{\pmb{\bigstar}}} \\ \\ \\ \end{gathered}$

$\therefore \;$ Body is at the Height of 3.63 m .

$\\ \qquad{\rule{200pt}{2pt}}$